The range of f(x) = |x| + |x – 3| + |x + 5| is?
Explanation:
Here the critical points are x = -5, 0, 3
∴ f(x) will be minimum when x = 0
⇒ Minimum value of f(x) = f(0) = 0 + 3 + 5 = 8
There is no limit on maximum value of f(x).
∴ f(x) ∈ [8, ∞)
Hence, option (d).
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