How many integral values of x satisfy the given quadratic inequality: x2 - 5x - 6 < 0?
Explanation:
Given, x2 – 5x – 6 > 0
⇒ (x - 6)(x + 1) > 0
This is only possible when (x - 6) is negative and (x + 1) is positive. ∴ -1 < x < 6
Integral values x can take are 0, 1, 2, 3 and 4, i.e., 5 values
Hence, 6.
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