Discussion

Explanation:

Given, x2 – 5x – 6 > 0

⇒ (x - 6)(x + 1) > 0

This is only possible when (x - 6) is negative and (x + 1) is positive.
∴ -1 < x < 6

Integral values x can take are 0, 1, 2, 3 and 4, i.e., 5 values

Hence, 6.

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