Discussion

Explanation:

Remember speed = distance/time, since distance covered is the same, say d and if t₁, t₂, t₃ be the time taken by the three cars, then,

$\frac{d}{t_1}:\frac{d}{t_2}:\frac{d}{t_3}=4 : 3 : 2$ or $\frac{1}{t_1}:\frac{1}{t_2}:\frac{1}{t_3}=4 : 3 : 2$

To find t₁ : t₂ : t₃, we must find inverse ratio of 4 : 3 : 2, i.e. 1/4 : 1/3 : 1/2 = $\frac{1\times 12}{4}:\frac{1\times 12}{3}:\frac{1\times 12}{2}$ = 3 ∶ 4 ∶ 6

Hence, option (c).

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