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Question:

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, $\frac{(x \times 14 \times 2)}{100} + \frac{(13900 - x) \times 11 \times 2}{100} = 3508$

⇒ 28x - 22x = 350800 - (13900 x 22)

⇒ 6x = 45000

⇒ x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Hence, option (a).

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