One of the tribeswoman initially had 2 gold, 3 silver and 10 bronze coins. She went to the market to buy a dress for herself. She bought one of the 4 dresses that the shopkeeper had. Which dress she could have bought?
Explanation:
Consider the solution to first question of this set. 1 gold coin = 10 bronze coins and 1 silver coin = 4 bronze coins.
Number of coins with tribeswoman = 2g + 3s + 10b
Total value of coins with tribeswoman in terms of bronze coins = 2 × 10b + 3 × 4b + 10b = 42b
Now, let us calculate the value of each of the options in terms of bronze coins.
Option (a): 1 × 10b + 5 × 4b + 15b = 45b
Option (b): 2 × 10b + 2 × 4b + 15b = 43b
Option (c): 3 × 10b + 2 × 4b + 4b = 42b
Option (d): 2 × 10b + 4 × 4b + 7b = 43b
Hence, she could’ve only bought dress 3.
Hence, option (c).
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