Discussion

Explanation:

(fog)(x) = f[g(x)] = f(|2x + 3|)

Since the domain of f(x) is [-6, 4]

⇒ -6 ≤ |2x + 3| ≤ 4

Since |2x + 3| ≥ 0

⇒ |2x + 3| ≤ 4

⇒ -4 ≤ 2x + 3 ≤ 4

⇒ -7 ≤ 2x ≤ 1

⇒ -3.5 ≤ x ≤ 0.5

∴ Domain of fog(x) is [-7/2, 1/2]

Hence, option (b).

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