Discussion

Explanation:

Let the first term of the GP be ‘a’ and the common ratio be ‘r’.

Given, ST2=163

a/(1-r)ar=163

1r(1-r)=163

⇒ 16r2  - 16r + 3 = 0

⇒ r = ¼ or 3/4

Since only ¼ is there in one of the options and there is no option as ’Cannot be determined’, we will mark the correct answer as option (a).

Hence, option (a).

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