Find the sum of the squares of the first 10 terms of the series whose sum up to n terms is given by n2 + 2n.
Explanation:
Sn = n2 + 2n
Tn = Sn – Sn-1
∴ Tn = (n2 + 2n) - ((n – 1)2 + 2(n – 1)) = 2n + 1
Sum of square of n terms = Σ(2n + 1)2
= Σ(4n2 + 2n + 1)
= 4Σn2 + 4Σn + Σ1
= 4n(n+1)(2n+1)6 + 4n(n+1)2 + n
∴ Sum of square of 10 terms = 410(10+1)(20+1)6 + 410(10+1)2 + 10
= 1540 + 220 + 10 = 1770.
Hence, 1770.
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