In the given figure, E and F are the centers of two identical circles. What is the ratio of area of triangle AOB to the area of triangle DOC?
Explanation:
∆AEB ≅ MED
∴ MD = AB
∆BFA ≅ NFC
∴ NC = AB
⇒ DM = AB = NC
⇒ DC = DM + MN + NC = 3AB
Now, ∆AOB ≈ ∆COD
∴ Area(∆AOB)Area(∆COD) = 132 = 19
Hence, option (b).
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