Discussion

Explanation:

​​​​​​​

∆AEB ≅ MED

∴ MD = AB

∆BFA ≅ NFC

∴ NC = AB

⇒ DM = AB = NC

⇒ DC = DM + MN + NC = 3AB

Now, ∆AOB ≈ ∆COD

∴ Area(AOB)Area(COD) = 132 = 19

Hence, option (b).

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