Discussion

Explanation:

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Let the radius of bigger circle (center X) be R cm.

Now, ∠QCY = ½ ∠BCA = 30°

∴ ∆CYQ is a 30°-60°-90° triangle

YQ = 2 ⇒ CY = 4 and CQ = 2√3

∆CXP is also a 30°-60°-90° triangle

∴ CX = 2 XP

⇒ (R + 2 + 4) = 2R

⇒ R = 6 cm

Hence, option (b).

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