Discussion

Explanation:

In ∆ABC and ∆QRC
∠B = ∠R = 90°
∠C is common
∴ ∆ABC ~ ∆QRC (A-A Rule)

ABQR=BCRC

⇒ 21QR=28RC

RCQR=2821=43

Let RC = 4x and QR = 3x = BR

​​​​​​​

∴ BR + RC = 7x = 28

⇒ x = 4

∴ Area of PQRB = 12 × 12 = 144.

Hence, option (c).

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