ABC is a right angled triangle with AB = 21 units and BC = 28 units. If PQRB is a square, find its area?
Explanation:
In ∆ABC and ∆QRC ∠B = ∠R = 90° ∠C is common ∴ ∆ABC ~ ∆QRC (A-A Rule)
⇒ ABQR=BCRC
⇒ 21QR=28RC
⇒ RCQR=2821=43
Let RC = 4x and QR = 3x = BR
∴ BR + RC = 7x = 28
⇒ x = 4
∴ Area of PQRB = 12 × 12 = 144.
Hence, option (c).
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