P and Q are two different alloys prepared by mixing 'copper' and 'iron' in the ratios of 9 : 4 and 9 : 17, respectively. Find the ratio of 'iron' to 'copper' in R, if equal quantities of these alloys are mixed to form a third kind of alloy R.
Explanation:
Let 26 kgs of P and Q are mixed to form R. (LCM((9 + 4), (9 + 17)))
26 kg of alloy P contains 18 kg of copper and 8 kg of iron.
26 kg of alloy Q contains 9 kg of copper and 17 kg of iron.
On mixing the two, we get 52 kg of alloy R, which has 27 kg of copper and 25 kg of iron.
Thus, the ratio of iron to copper in mixture R is 25 : 27.
Hence, option (b).
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