One solution of metal contains 90% milk and 10% water. Another solution contains 93% milk and 4% water. Later, they are mixed, so that the mixture contains 9% of water. What percent of milk will it contain?
Explanation:
Let the x liters of first and 100 liters of second solution be mixed.
∴ 10% of x + 4% of 100 = 9% of (x + 100)
⇒ 10x + 400 = 9(x + 100)
⇒ x = 500
∴ Total quantity of mixture = 100 + 500 = 600 liters
Amount of milk = 90% of 500 + 93% of 100 = 450 + 93 = 543 liters
∴ % of milk = 543/600 × 100 = 90.5%
Hence, option (d).
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