Discussion

Explanation:

Let the first term be a and the common ratio be r.

Given, each term of the the GP is twice the sum of all the following terms.

Let’s consider the 3rd term of the G.P.

∴ ar2 = ar3 + ar4 + ar5 + … ∞

⇒ ar2 = (ar3)/(1-r)

⇒ 1 – r = r

⇒ r = ½

Hence, option (a).

» Your doubt will be displayed only after approval.


Doubts


Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All