What will be the maximum sum of 52, 50, 48 …
Explanation:
Maximum sum will occur when last term is 0 or 2 (since after that terms will be -ve which will start reducing the sum)
∴ Last term = 0 = 52 + (n – 1)(-2)
⇒ n = 27
∴ Smax = 27/2 × [52 + 0] = 702.
Hence, option (b).
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