Discussion

Explanation:

The given number are 13, 17 …….. 97. 

This is an A.P. with first term 13 and common difference 4. 

Let the number of terms be n. 

Then 97 = 13 + (n – 1)4 

⇒ 4n = 88 

⇒ n = 22

∴ Sum of the numbers = n/2 × [First term + Last term] = 22/2 × [13 + 97] = 11 × 110 = 1210.

Hence, option (c).

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