Discussion

Explanation:

Let speed of boatman in still water be b and speed of current = r.

Initially, 

Speed of boat against the current = b – r

Speed of boat with the current = b + r

Since the boat covers twice the distance downstream as compared to upstream in the same time, it means downstream speed is twice that of upstream speed.

∴ b + r = 2(b - r)

⇒ b = 3r   …(1)

Now, when speed of current is increased by 2 kmph, upstream speed is 5 times downstream speed.

∴ (b + r + 2) = 5(b – (r + 2))

⇒ 4r + 2 = 5(2r - 2)

⇒ r = 2 and b = 6 kmph.

Hence, option (d).

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