Two ants start simultaneously from two ant holes towards each other. The first ant covers 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.
Explanation:
Let the distance between the two ant holes be 600d feet.
∴ Speed of first ant = 600d×81003 = 16d feet/hr
∴ Speed of second ant = 600d×71202.5 = 14d feet/hr
Till meeting point first ant travels 800 ft and second ant travels 600d – 800 ft.
∴ 800600d-800=16d14d
⇒ 700 = 600d – 800
⇒ d = 2.5
∴ Speed of second ant and = 14 × 2.5 = 35 feet/hr
Hence, option (d).
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.