Discussion

Explanation:

Let the distance between the two ant holes be 600d feet.

∴ Speed of first ant = 600d×81003 = 16d feet/hr

∴ Speed of second ant = 600d×71202.5 = 14d feet/hr

Till meeting point first ant travels 800 ft and second ant travels 600d – 800 ft.

800600d-800=16d14d

⇒ 700 = 600d – 800

⇒ d = 2.5

∴ Speed of second ant and = 14 × 2.5 = 35 feet/hr

Hence, option (d).

» Your doubt will be displayed only after approval.


Doubts


Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All