Two persons start from the opposite ends of a 60 km straight track and run to and from between the two ends. The speed of first person is 10 m/s and the speed of other is 125/18 m/s. They continue their motion for 10 hours. How many times they pass each other?
Explanation:
The speed of two persons is 36 km/h and 25 km/h.
When 2 people start from opposite ends and to and fro between the two ends, time taken to meet for nth time
= 2n-1Da+b [Here, ½< a/b < 2]
∴ (2n-1)×6036+25 ≤ 10
⇒ 2n – 1 ≤ 61/6
⇒ n ≤ 5.6
∴ Both of them will meet 5 times in 10 hours.
Hence, option (a).
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