Two runners run in the same direction along a circular track of 2 km long. The faster runner overtakes the slower one in every 30 minutes. Find their speeds if the faster one completes the track one minute sooner than the other.
Explanation:
Let x km/h and y km/h be the speeds of the two runners x > y
As per the question, 2y-2x=160 …(1)
Also faster runner covers (x – y) km more than slower in 1 hr.
So, he will gain 2 km in 2(x-y) hr or 1/2 hr. (30 min)
2x-y=12 or, x – y = 4 …(2)
On solving (1) and (2), we get x = 24 km/h y = 20 km/h
Hence, option (a).
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