Discussion

Explanation:

Let the speed of the train and the car be t km/h and c km/h, respectively.

Now, $\frac{300}{t}+\frac{200}{c}$ = 8   …(1)

and $\frac{300}{c}+\frac{200}{t}$ = 7   …(2)

From (1), 300c + 200t = 8ct and    …(3)

From (2), 300t + 200c = 7ct    …(4)

From (3) and (4), eliminating ct term we get

t : c = 1 : 2

Hence, option (c).

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