Discussion

Explanation:

Let the length of each of the candles be 1 unit.

Let the first candle be twice the length of second candle after x hours of burning.

Amount of candle 1 burnt in x hours = x/6
Amount of candle 2 burnt in x hours = x/4

After x hours of burning, length remaining of
Candle 1: (1 – x/6)
Candle 2: (1 – x/4)

∴ (1 – x/6) = 2 × (1 – x/4)

⇒ 1 – x/6 = 2 – x/2

⇒ x = 3

∴ After 3 hours the first candle is twice the length of second.

Hence, option (a).

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