Discussion

Explanation:

​​​​​​​

EA is the line representing the ground.

Height of the man (represented by AB) = 1 meter.

Let height of the pole (ED) = x meters.

In ∆BFD, tan45° = 1 = DF/BF

⇒ BF = DF   …(1)

In ∆BFD, tan60° = √3 = CF/BF

⇒ BF = CF/√3   …(2)

From (1) and (2)

DF = CF/√3

⇒ x – 1 = (x + 1)/√3

⇒ √3x - √3 = x + 1

⇒ √3x - x = 1 + √3

⇒ x = (√3 + 1)/(√3 - 1)

⇒ x = (√3 + 1)2/2

⇒ x = (4 + 2√3)/2 = 2 + √3

Hence, option (c).

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