Discussion

Explanation:

​​​​​​​

Given, BC = 50 m.

Let CD = x.

In ∆ ABC, tan45° = 1/√3 = BC/AB

⇒ AB = BC × √3 = 50√3.

In ∆ ABD, tan45° = 1 = BD/AB

⇒ BD = AB

⇒ 50 + x = 50√3

⇒ x = 50(√3 - 1)

Hence, option (a).

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