Discussion

Explanation:

Given, f(x + y) = f(x) × f (y) and f(1) = 2.

Putting x = y = 1, f(2) = f(1) × f(1) = 22

Putting x = 1 and y = 2, f(3) = f(1) × f(2) = 23

… and so on.

We can see that f(x) = 2x.

Now, we have, f(1) + f(2) + f(3) + ……f(n) = 510

⇒ 21 + 22 + 23 + … + 2n = 510

⇒ 2n+1 – 2 = 510

⇒ 2n+1 = 512 = 29

⇒ n + 1 = 9

⇒ n = 8.

Hence, option (d).

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