Discussion

Explanation:

Let a = 3k, b = 7k

∴ $\frac{4a+b}{3a+5b}=\frac{4\times 3k+7k}{3\times 3k+5\times 7k}$ = $\frac{19k}{44k}=\frac{19}{44}$

Hence, option (d).

Alternately,

We have to find the value of $\frac{4a+b}{3a+5b}$

Dividing both numerator and denominator with b, we get

$\frac{4\left({\displaystyle \frac{a}{b}}\right)+1}{3\left({\displaystyle \frac{a}{b}}\right)+5}=\frac{4\left({\displaystyle \frac{3}{7}}\right)+1}{3\left({\displaystyle \frac{3}{7}}\right)+5}$ = $\frac{12+7}{9+35}=\frac{19}{44}$ 

Hence, option (d).

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