Discussion

Explanation:

When two players play a game such that 

• they pick balls alternately, 
• each player can pick balls from 1 to n,
• last player to pick loses.

The winning strategy in such scenario is to leave ((n+1)k + 1) marbles in your turn.

Whoever picks marbles from ((n+1)k + 1) marbles, he/she will lose.

For Surya to lose the game he should have picked the first time from (4k + 1) marbles.

From the options given, 9 and 13 are of the form 4k + 1. The least of these is 9.

Hence, option (b).

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