Discussion

Explanation:

P α (Q+R)

⇒ P = k(Q+R)

Also,Q α x ⇒ Q =k1x

and, R α 1/x ⇒ R = k2/x 

P = kk1x + kk2/x

= p1x + p2/x  (where p1 and p2 are constants)

⇒ 4p+ p2/4 = 12

⇒ 16p+ p= 48    …(1)

and, 8p+ p2/8 = 18

⇒ 64p+ p= 144    …(2)

Solving (1) and (2), 

we get∶ p= 2 and, p= 16

∴ A = 2x + 16/x

When, x = 16, A = 32 + 1 = 33

Hence, option (d).

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