Discussion

Explanation:

Let’s first calculate P (1^st blue, 2^nd red & 3^rd black) = $\frac{5}{15}\times \frac{6}{15}\times \frac{4}{15}$ = $\frac{120}{3375}$

Now, the sequence of drawing three colors can be in 3! = 6 ways.

∴ We multiply the above probability with 6 to get the final answer.

∴ Required answer = $\frac{120}{3375}\times 6$ = $\frac{80}{375}$ = $\frac{16}{75}$

Hence, option (a).

» Your doubt will be displayed only after approval.