PE 1 - Tables & Graphs

Milk at the end of Monday is 600 liters and at the start of Tuesday is 400 liters.

⇒ The milk thrown away on Tuesday is 600 – 400 = 200 liters.  

This is the spoilt milk which was produced on Monday. Hence, the consumable milk produced on Monday is 600 – 200 = 400 liters.

Half of this 400 liters consumable milk will be thrown away on Wednesday i.e. 200 consumable milk will be thrown away on Wednesday.

Total milk thrown away on Wednesday = 760 – 400 = 360. 200 liters of this is consumable milk produced on Monday and rest 360 – 200 = 160 liters is the spoilt milk produced on Tuesday.

Total milk produced on Tuesday = 760 – 400 = 360 liters.

∴ Consumable milk produced on Tuesday is 360 – 160 = 200 liters.

Similarly, we can complete the entire table till Friday.

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∴ Total consumable milk produced till Thursday = 400 + 200 + 100 + 120 = 820 liters.

Hence, option (d).

Consider the solution to the first question of this set.

200 liters of consumable milk was thrown away at the start of Wednesday.

Hence, option (a).

Consider the solution to the first question of this set.

Maximum quantity of spoilt milk produced from Monday to Thursday is 280 liters on Thursday.

Hence, option (b).

Consider the solution to the first question of this set.

Consumable milk left at the end of Thursday = 0.5 × 400 + 0.5 × 200 + 100 + 120 = 5620 liters.

Hence, 520.

Ratio of market size of each of these 5 categories is given.

Let the market size of Bell-bottom, Straight-fit, Cropped, Ripped and Low-waist be 100, 500, 300, 400 and 200 respectively.

∴ These 5 manufacturers account for 80%, 60%, 90%, 75% and 40% respectively in each of these 5 categories.

∴ Market share of these 5 manufacturers is 80% of 100, 60% of 500, 90% of 300, 75% of 400 and 40% of 200 i.e., 80, 300, 270, 300 and 80 respectively.

Manufacturer A has 30%, 20%, 10%, 35% and 20% share across these categories.

∴ Market share of these manufacturer A is 30% of 80, 20% of 300, 10% of 270, 35% of 300 and 20% 80 i.e., 24, 60, 27, 105 and 16 respectively.

∴ % revenue from Rippped jeans for  A = $\frac{105}{24+60+27+105+16}$ × 100 = 45%.

Hence, option (c).

Total market size of Bell-bottom jeans = Rs. 30 crores.

∴ Market share of these 5 manufacturers = 80% of 30 = Rs. 24 crores.

∴ Market share of C from bell bottom = 20% of 24 = Rs. 4.8 crores.

Given,

Market share of C from bell bottom = Market share of A and B from Straight-fit = Rs. 4.8 crores.

Market share of B and C from Straight-fit = 40% of Market share of all 5 manufacturers.

∴ Market share of all 5 manufacturers = 4.8/0.4 = Rs. 12 crores.

Market share of all 5 manufacturers = 60% of Market size of Straight-fit.

∴ Market size of Straight-fit jeans = 12/0.6 = Rs. 20 crores

Hence, option (b).

Let the market size of Cropped jeans and Low-waist jeans be x and y respectively.

Revenue of D from Cropped jeans = 15% of 90% of x = 27x/200

Revenue of E from Low-waist jeans = 5% of 40% of y = y/50

∴ 27x/200 = y/50

⇒ x : y = 4 : 27.

Hence, option (a).

Let the total market size of Bell-bottom, Straight-fit and Ripped be x, y and z respectively.

For Bell-bottom highest revenue is generated by A = 30% of 80% of x = 6x/25

For Straight-fit highest revenue is generated by C = 30% of 60% of x = 9y/50

For Ripped highest revenue is generated by A = 35% of 75% of x = 21z/80

According to the question,

⇒ $\frac{6x}{25}=\frac{9y}{50}=\frac{21z}{80}$

Dividing by 126 we get

$\frac{x}{525}=\frac{y}{700}=\frac{z}{480}$

∴ x : y : z = 525 : 700 : 480 = 105 : 140 : 96.

Hence, option (c).