CRE 3 - Pie-Charts

Expenditure on food = $\frac{90}{360}\times 9 lakh$ = 2.25 lakh

Expenditure on travel= $\frac{65}{360}\times 9 lakh$ = 1.625 lakh

$\frac{Expenditre on Food}{Expenditre on Travel}$ = $\frac{2.25}{1.625}$ = $\frac{18}{13}$

Alternately,
In this case the ratio of respective angles will give us the ratio of expenditures.

∴ $\frac{Expenditre on Food}{Expenditre on Travel}=\frac{90}{65}=\frac{18}{13}$

Hence, option (a).

Total angle covered by Food and Education = 90° + 70° = 160°.

fraction of expenditure on Food and Education = $\frac{160}{360}$

Total expense on Food and Education = $\frac{160}{360}$ × 9 lakh = 4 lakh.

Hence, 400000.

Amount spent on medicines = 80/360 × 9 lakh = 2 lakh.

Hence, option (c).

If the difference of angles is same, the difference of expenditures will also be same. Hence, we will simply check for difference in angles.

Difference in amount spent on Food and Medicines = 90° – 80° = 10°.

Using options, only option (d) i.e., Travel – Rent = 65° - 55° = 10°.

Hence, option (d).

Difference in angle between Food and Travel = 90° - 65° = 25°.

⇒ % difference = 25/65 × 100 = 38.46%

Hence, option (a).

Petroleum is 10% of total exports i.e., 10% of 1440.

⇒ Value = 10/100 × 1440 = 144

Hence, option (c).

Mobiles are 15% of total exports i.e., the central angle made by mobile sector will also be 15% of 360°.

⇒ Angle = 15/100 × 360 = 54°

Hence, option (b).

Wheat is 30% of total exports while Rice is .20% of total exports.

$\frac{Wheat}{Rice}=\frac{30\% of Total}{20\% of Total}$ = $\frac{30}{20}$ = $\frac{3}{2}$

Hence, option (d).

Average = 1440/5 = 288 crores.

Hence, 288.

We need to check for options here.

Only option (b) gives the same % value for both the pair i.e.,

Gold + Rice = 45% of Total exports and

Wheat + Mobile = 45% of Total exports

Hence, option (b).

Option (a):
The number of employees with 3 projects in 2010 = 19% of 60 = 11,400
The number of employees with 3 projects in 2020 = 15% of 80 = 12,000
Thus, the number of employees with 3 projects increased from 2010 to 2020. 
Thus, option (c) is not true.

Option (b):
The number of employees with projects in 2010 = 89% of 60,000 = 53,400
The number of employees with projects in 2020 = 91% of 80 = 72,800
Thus, there were more employees with projects in 2020 than in 2010. 
Thus, option (a) is not true.

Option (c):
The number of employees with 2 or more projects in 2010 = 61% of 60,000 = 36,600
The number of employees with 2 or more projects in 2020 = 66% of 80 = 52,800
Thus, there were more employees with 2 or more projects in 2020 than in 2010. 
Thus, option (b) is not true.

Thus, none of the statements are true. 

Hence, option (d).

We know the exact number of employees with no project, exactly one project and exactly two projects. But we don’t know the number of employees with exactly 3 or any higher number of projects. Hence, we will not be able to calculate the total number of projects in 2020.

Hence, the average number of projects per employee cannot be found. 

Hence, option (d).

The number of employees in 2010 and 2020 is 60 and 80 million respectively.

Growth from 2010 till 2020 = $\frac{80-60}{60}$ × 100% = 33.33%

The simple average annual growth rate = $\frac{33.3\%}{10}$ = 3.33%

Hence, option (b).

The information about average number of projects in this question is redundant. 

Number of employees without any project in 2020 is 9% of 80,000 = 7,200.

Hence, 7200.