# CRE 1 - Tables | DI - Tables & Graphs

**Answer the next 5 questions based on the information given below:**

Sale of Seven companies from 2007-08 to 2013-14

**CRE 1 - Tables | DI - Tables & Graphs**

What is the increase in the sales of the companies A, B and C together from 2007-08 to 2013-14?

- A.
Rs. 700 crore

- B.
Rs. 1200 crore

- C.
Rs. 1000 crore

- D.
Rs. 800 crore

Answer: Option C

**Explanation** :

The increase in the sales of the companies A, B and C together from 2007-08 to 2013-14

= Rs. (760 + 600 + 560) – (360 + 320 + 240)

= Rs. 1920 – Rs. 920

= Rs. 1000

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

What is the ratio of the sales of the companies E, F and G together in 2008-09 to that in 2009-10?

- A.
8 : 9

- B.
10 : 11

- C.
12 : 13

- D.
14 : 15

Answer: Option A

**Explanation** :

The ratio of the sales of the companies E, F and G together in 2008-09 to that in 2009-10

= (320 + 280 + 360) : (360 + 320 + 400)

= 960 : 1080

= 8 : 9.

Hence, option (a).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

What is the percentage increase in the sales of the companies A, C and E together from 2007-08 to 2013-14?

- A.
100%

- B.
88%

- C.
113%

- D.
125%

Answer: Option C

**Explanation** :

The percentage increase in the sales of the companies C, E and F together from 2007-08 to 2013-14

= (1880 - 880)/880 × 100% ≈ 113%.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

From 2007-08 to 2013-14, which of the given companies has the lowest percentage increase in sales?

- A.
G

- B.
B

- C.
E

- D.
D

Answer: Option B

**Explanation** :

By observation we can see that sales for all companies except B at least doubled during the given period. Hence, the growth in sales for each of these companies is greater than or equal to 200%.

For B the sales increased by a factor less than 2. Hence, the growth in sales for B is less than or equal to 200%.

⇒ Growth rate is least for company B.

**Alternately,**

The following table shows the percentage increase in the sales of the companies from 2007-08 to 2013-14.

Company |
% increase in sales |

A | 111.11% |

B | 87.5% |

C | 133.33% |

D | 100% |

E | 100% |

F | 150% |

G | 100% |

Clearly for the company B, the percentage increase was the lowest.

Hence, option (b).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

In which year the sales of the companies C, D and E together increase the highest when compared to respective previous year?

- A.
2011-12

- B.
2010-11

- C.
2013-14

- D.
2008-09

Answer: Option C

**Explanation** :

The following table shows the sales of C, D and E together in the given years and the respective increase in the sales.

Years |
Sales of C, D and E |
Increase in sales |

2007-08 | 820 | - |

2008-09 | 940 | 120 |

2009-10 | 1040 | 100 |

2010-11 | 1200 | 160 |

2011-12 | 1380 | 180 |

2012-13 | 1520 | 140 |

2013-14 | 1720 | 200 |

Clearly, the required increase is the highest in 2013-14.

Hence, option (c).

Workspace:

**Answer the next 5 questions based on the information given below.**

Average marks obtained by 50 boys and 50 girls in each of the five schools S1 to S5 in five subjects.

**CRE 1 - Tables | DI - Tables & Graphs**

In which of the following subjects did the boys have lowest average percentage of marks from all the schools?

- A.
Maths

- B.
Social

- C.
Hindi

- D.
Science

Answer: Option C

**Explanation** :

English : $\frac{\left(104+160+136+144+140\right)\times 50}{250\times 300}\times 100$ = $\frac{\left(104+160+136+144+140\right)}{5\times 300}\times 100$ = 45.6%

Maths : $\frac{(200+160+160+240+240)\times 50}{250\times 400}\times 100$ = $\frac{(200+160+160+240+240)}{5\times 400}\times 100$ = 50%

Science : $\frac{\left(160+168+150+180+160\right)\times 50}{250\times 300}\times 100$ = $\frac{\left(160+168+150+180+160\right)}{5\times 300}\times 100$ = 54.5%

Social : $\frac{\left(168+160+150+170+180\right)\times 50}{250\times 300}\times 100$ = $\frac{\left(168+160+150+170+180\right)}{5\times 300}\times 100$ = 55.2%

Hindi : $\frac{\left(80+96+84+90+84\right)\times 50}{250\times 200}\times 100$ = $\frac{\left(80+96+84+90+84\right)}{5\times 200}\times 100$ = 43.4%

In Hindi boys secured the lowest average percentage.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

What was the total marks obtained by girls in Maths from school S2?

- A.
14,000

- B.
6,500

- C.
7,200

- D.
16,000

Answer: Option A

**Explanation** :

Total marks of girls from S2 in maths = 280 × 50 = 14000.

Hence, option (a).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

In case of which one of the following schools the total marks obtained by girls in Maths was 50% more than the total marks obtained by boys in Social from school S2?

- A.
S4

- B.
S5

- C.
S2

- D.
S3

Answer: Option D

**Explanation** :

Total marks obtained by boys in S2 in social studies = 160 × 50 = 8000

Required total of girls = 8000 + 50% of 8000 = 12000.

∴ Average marks of girls in Maths should be 12000/50 = 240.

This is equal to the average marks obtained by girls in school S3.

**Alternately,**

Since the number of boys or girls in any school is same, we need not calculate total marks.

If the average of boys in S2 in social is 160, the average of girls in maths should be 160 × 1.5 = 240

Girls from S3 have average of 240 in maths.

Hence, option (d).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

What is the ratio of total marks obtained in English by students in school S2 to those obtained in science by students in school S4?

- A.
122 : 185

- B.
91 : 111

- C.
82 : 93

- D.
11 : 15

Answer: Option C

**Explanation** :

Since the number of boys or girls in any school is same, we need not calculate total marks.

Average marks of students of school S2 in English = (160 + 168)/2 = 164

Average marks of students of school S4 in Science= (180 + 192)/2 = 186

Required ratio = 164 : 186 = 82 : 93.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

In which one of the following subjects did the girls have the highest average percentage marks from all the schools?

- A.
Social

- B.
Maths

- C.
Hindi

- D.
English

Answer: Option B

**Explanation** :

English : $\frac{\left(116+168+130+150+144\right)\times 50}{250\times 300}\times 100$ = $\frac{\left(116+168+130+150+144\right)}{5\times 300}\times 100$ = 47.2%

Maths : $\frac{\left(250+280+240+280+320\right)\times 50}{250\times 400}\times 100$ = $\frac{\left(250+280+240+280+320\right)}{5\times 400}\times 100$ = 68.5%

Science : $\frac{\left(180+180+150+192+184\right)\times 50}{250\times 300}\times 100$ = $\frac{\left(180+180+150+192+184\right)}{5\times 300}\times 100$ = 59.1%

Social : $\frac{\left(150+168+192+180+184\right)\times 50}{250\times 300}\times 100$ = $\frac{\left(150+168+192+180+184\right)}{5\times 300}\times 100$ = 58.3%

Hindi : $\frac{\left(104+100+96+112+96\right)\times 50}{250\times 200}\times 100$ = $\frac{\left(104+100+96+112+96\right)}{5\times 200}\times 100$ = 50.8%

The highest is in Maths.

Hence, option (b).

Workspace:

**Answer the next 5 questions based on the information given below.**

These questions are based on the following table which shows the annual production of Coffee and Mate in selected states of USA for the year 2016-2017.

**CRE 1 - Tables | DI - Tables & Graphs**

How many of the mentioned states failed to cross the threshold yield of 0.1 ton of Coffee per hectare of area under Coffee Production?

- A.
0

- B.
1

- C.
2

- D.
3

- E.
Cannot be determined

Answer: Option C

**Explanation** :

Here we need to calculate the coffee yield which is coffee produced (tons) per hectare of area under coffee production.

∴ Yield = $\frac{\mathrm{Coffee}\mathrm{produced}}{\mathrm{Area}\mathrm{under}\mathrm{coffee}\mathrm{production}}$

Let us calculate the yield for California.

Coffee produced = 1.3 × 1000 tons

Area under coffee production = 21 × 10,000 × 5/100 hectares

∴ Yield = $\frac{1.3\times 1000}{21\times 10,000\times {\displaystyle \frac{5}{100}}}$ = $\frac{1.3}{21\times 5}$ × 10

Note: The factor of 10 will be same for all the states, hence to calculate yield for other states we will only have to change the corresponding values of 1.3, 21 and 5.

Yield for California = $\frac{13}{105}$5 > 0.1 [∵ 13 > 105 × 0.1]

Yield for Hawaii = $\frac{4.9}{48\times 10}$ × 10 = $\frac{49}{480}$ > 0.1 [∵ 49 > 480 × 0.1]

Yield for Florida = 12.5/(90×12) × 10 = 125/1080 > 0.1 [∵ 125 > 1080 × 0.1]

Yield for Arizona = 5.6/(31×8) × 10 = 56/248 > 0.1

Yield for Colorado = 6.1/(25×20) × 10 = 61/500 > 0.1

Yield for Idaho = 5.6/(33×15) × 10 = 56/495 > 0.1

Yield for Illinois = 2.1/(19×12) × 10 = 12/228 < 0.1 [∵ 12 < 228 × 0.1]

Yield for Georgia = 2.6/(27×10) × 10 = 26/270 > 0.1 [∵ 26 < 270 × 0.1]

Yield for Indiana = 7/(34×6) × 10 = 70/204 > 0.1 [∵ 70 > 204 × 0.1]

Yield for Iowa = 2.9/(25×8) × 10 = 29/200 > 0.1

Yield for Kentucky = 3.6/(160×2) × 10 = 36/320 > 0.1

Yield for Maryland = 1.4/(19×5) × 10 = 14/95 > 0.1

Two states i.e., Illinois and Georgia failed to cross the threshold yield of 0.1.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

How many of the given states with a population less than 20 million, produce more Coffee than Mate?

- A.
4

- B.
3

- C.
2

- D.
1

- E.
5

Answer: Option C

**Explanation** :

Colorado and Iowa are the only 2 states with population less than 20 million which produce more coffee than mate.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

How many of the given states have a total area (in hectare) per ton of Mate production > 100 and a population of at least 13 million?

- A.
5

- B.
1

- C.
4

- D.
3

- E.
2

Answer: Option C

**Explanation** :

Here we need to calculate $\frac{\mathrm{Total}\mathrm{Area}}{\mathrm{Mate}\mathrm{Production}}$ for states with population ≥ 13 million.

Let us start with Hawaii

$\frac{\mathrm{Total}\mathrm{Area}}{\mathrm{Mate}\mathrm{Production}}$ = $\frac{48\times 10,000}{3.5\times 1000}$ = $\frac{48}{3.5}$ × 10

Here, the factor of 10 will remain the same for all states upon simplification. We just need to change the corresponding values of 48 and 3.5 for other states.

Yield for Hawaii = 48/3.5 × 10 = 480/3.5 > 100 [∵ 480 > 3.5 × 100]

Yield for Florida = 90/7.2 × 10 = 900/7.2 > 100 [∵ 900 > 7.2 × 100]

Yield for Arizona = 31/6.4 × 10 = 310/6.4 < 100 [∵ 310 < 6.4 × 100]

Yield for Idaho = 33/8 × 10 = 330/8 > 100 [∵ 330 > 8 × 100]

Yield for Kentucky = 160/11.1 × 10 = 1600/11.1 > 100 [∵ 1600 > 11.1 × 100]

Yield for Maryland = 19/1.9 × 10 = 190/1.9 = 100 [∵ 190 = 1.9 × 100]

∴ There are 4 states for whom the ratio is > 100.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

International price of Coffee and Mate are $3000 per ton and $300 per ton respectively. Which state earned the highest revenue through export of Coffee and Mate, if all states exported their entire Coffee and Mate production at the given international price?

- A.
Florida

- B.
Idaho

- C.
Arizona

- D.
Indiana

- E.
Colorado

Answer: Option A

**Explanation** :

Total revenue = 3000 × C + 300 × M = 300(10C + M)

The revenue will be highest of that state for which (10C + M) is highest.

Of the options given, the value of (10C + M) is highest for Florida.

Hence, option (a).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

If the domestic consumption of Coffee in USA is 60% of its production and the rest of the Coffee production gets exported at a price of $2000 per ton, what is the revenue earned by USA through Coffee exports? [Assume these mentioned states account for 80% of US’s Coffee Production]

- A.
$42.8 million

- B.
$55.6 million

- C.
$49.2 million

- D.
$64.8 million

- E.
$44.5 million

Answer: Option B

**Explanation** :

Coffee Production in the given states = 55.6 × 1000 tons.

These given states account for 80% of US’s coffee production.

∴ US coffee production = $\frac{55.6}{0.8}$ × 1000 tons.

40% of this production is exported.

⇒ Amount of coffee exported = $\frac{55.6}{0.8}$ × 1000 × 0.4 tons

Price of export is $2000/ton

⇒ Total export revenue = $\frac{55.6}{0.8}$ × 1000 × 0.4 × 2000 = $55.6 million

Hence, option (b).

Workspace:

**Answer the next 5 questions based on the information given below.**

These questions are based on the following table which shows the sales (volume) of 6 different mobile companies from the year 2015-16 through 2020-21.

**CRE 1 - Tables | DI - Tables & Graphs**

During the entire given period (2015-16 till 2021-22), the growth in the sales of the product that witnessed the highest growth is approximately what percentage of the growth in the sales of the product that showed the least growth?

- A.
709%

- B.
2220%

- C.
667%

- D.
454%

- E.
None of these

Answer: Option E

**Explanation** :

Growth for:

OnePlus = 68175 – 34500 = 33675

Samsung = 20250 – 18000 = 2250

Apple = 120000 – 49500 = 70500

Oppo = 9900 – 4500 = 5400

Vivo = 26100 – 9450 = 16650

Sony = 70200 – 20250 = 49950

Highest growth = 70500

Least growth = 2250

∴ Required answer = 2250/70500 × 100% > 3000%

Hence, option (e).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

For how many of the products are their sales in 2018-19 more than that of the average sales of all the products in 2018-19?

- A.
2

- B.
3

- C.
4

- D.
1

- E.
None of these

Answer: Option B

**Explanation** :

Average sales for 2018-19 = $\frac{45000+26550+58500+5625+11700+45450}{6}$ = 32137.5

∴ Sales for OnePlus, Apple and Sony is higher than average sales.

Hence, option (b).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

If ‘x’ is the percentage increase in the sales of each product from 2017-18 to 2021-22, then for how many products is 50 < x < 90?

- A.
1

- B.
2

- C.
3

- D.
4

- E.
0

Answer: Option C

**Explanation** :

Here we need not actually calculate the exact % increase in sales of each product.

A faster way would be to just check whether the % change in more than 50% or not and less than 90% of not.

[Note: We know to increase a number by 50% we add half of the number with itself and to increase a number by 90% (100% - 10%) we double the number and then subtract 10% of it.]

For **OnePlus** sales increase from 38,250 to 68175

Let us consider the initial sales i.e., 38,250. If this were to increase 50% it would become 38250 + 19125 = 57375. But the final sales is greater than this, hence % increase is more than 50%.

Now, if initial sales were to increase 90% it would become 38250 × 2 – 3825 = 72675. But the final sales is less than this, hence % change is less than 90%.

For Samsung sales decreases from 23400 to 20250, hence % change is less than 50%.

For Apple sales more than doubles from 54000 to 120000, hence % change is more than 90%.

For Oppo sales increases from 5400 to 9900. % change is definitely more than 50%. For 90% increase the final sales should be 5400 × 2 – 540 = 10,260. Since the final sales is less than this, the % change is less than 90%.

For Vivo sales increases from 14535 to 26100. % change is definitely more than 50%. For 90% increase the final sales should be 14535 × 2 – 1453.5 = 27634.5. Since the final sales is less than this, the % change is less than 90%.

For Sony sales more than doubles from 31500 to 70200, hence % change is more than 90%.

∴ For 3 products i.e., OnePlus, Oppo and Vivo, the % increase from 2017-18 to 2021-22 is between 50% and 90%.

Hence, option (c).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

During the given period what is the ratio of the total sales of Apple to that of Vivo and Sony together?

- A.
.068

- B.
1.138

- C.
1.223

- D.
0.942

- E.
0.882

Answer: Option B

**Explanation** :

Total sales for

Apple = 49500 + 51750 + 54000 + 58500 + 72000 + 82350 + 120000 = 488100

Vivo = 9450 + 11250 + 14535 + 11700 + 18450 + 23400 + 26100 = 114885

Sony = 20250 + 23850 + 31500 + 45450 + 59400 + 63000 + 70200 = 313650

Total sales of Vivo and Sony together = 114885 + 313650 = 428535

∴ The required ratio = $\frac{488100}{428535}$ = $\frac{428535+59565}{428535}$ = 1 + $\frac{59565}{428535}$ = 1 + 0.138 = 1.138

Hence, option (b).

Workspace:

**CRE 1 - Tables | DI - Tables & Graphs**

Whenever the sale of any company increases by more than 10% over the previous year, it throws a party for its sales team. During the given period, how many parties were organized?

Answer: 22

**Explanation** :

To check if % change if more or less than 10% we will simply increase the number by 10% and see if the actual number is more than this or not.

For **OnePlus**:

2015-16 to 2016-17: Initial sales is 34500. If this were to increase by 10% it would become 34500 + 3450 = 37950. Since the actual sales increases to 36000 (less than 37950), hence the % increase is less than 10%.

2016-17 to 2017-18: Initial sales is 36000. If this were to increase by 10% it would become 36000 + 3600 = 39600. Since the actual sales increases to 38250 (less than 39600), hence the % increase is less than 10%.

2017-18 to 2018-19: Initial sales is 38250. If this were to increase by 10% it would become 38250 + 3825 = 42075. Since the actual sales increases to 45000 (more than 42075), hence the % increase is more than 10%. A party will be organized.

2018-19 to 2019-20: Initial sales is 45000. If this were to increase by 10% it would become 45000 + 4500 = 49500. Since the actual sales increases to 54000 (more than 49500), hence the % increase is more than 10%. A party will be organized.

2019-20 to 2020-21: Initial sales is 54000. If this were to increase by 10% it would become 54000 + 5400 = 59400. Since the actual sales increases to 59000 (equal to 59400), hence the % increase is exactly equal to 10%. A party will not be thrown for exact 10% increase.

2020-21 to 2021-22: Initial sales is 59400. If this were to increase by 10% it would become 59400 + 5940 = 65340. Since the actual sales increases to 68175 (more than 65340), hence the % increase is more than 10%. A party will be organized.

OnePlus will throw a party 3 times during the given time-period.

Similarly,

**Samsung **will throw a party 3 times during the given time-period.

**Apple **will throw a party 3 times during the given time-period.

**Oppo **will throw a party 3 times during the given time-period.

**Vivo **will throw a party 5 times during the given time-period.

**Sony **will throw a party 5 times during the given time-period.

∴ Total parties organized = 3 + 3 + 3 + 3 + 5 + 5 = 22.

Hence, 22.

Workspace:

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