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A shopkeeper gives a discount of 20% on cost price of tea, but uses a weight of 800 gm per kg. Find his net profit / loss percentage.
Answer: A
Due to wrong weight, he is making profit of 200/800×100=25%. But since he is giving a discount of 20%, so net profit/loss
= 25 – 20 + (25 × -20))/100 = 5 - 5 = 0
Hence, option (a).
A shopkeeper professes to sell his product at cost price but uses a weight of 800gm in case of a kg. Find his real profit%
Answer: A
% profit = 200/800 × 100 = 25%
Hence, option (a).
A shopkeeper who professes to sell his goods at cost price uses a 900 gm weight for a kg. His gain percentage is
Answer: E
Gain% = ((error))/((True value - error) ) × 100
Gain% = 100/900 × 100 = 11(1/9)%
Hence, option (e).
A dealer professes to sell his goods at cost price, but he uses a false weight and gains %. For a kg, he uses a weight of
Answer: A
If he uses a weight of x gm, then profit percentage = (1000 - x)/x × 100, which is equal to 11(1/9)%
Therefore, x = 900 gms.
Hence, option (a).
A shopkeeper cheats while buying as well as while selling. While buying he takes 20% more than what he pays for and while selling he gives 20% less than what he charges for. If his selling price per kg is same as his cost price per kg, what is his profit percentage?
Answer: C
Buying: If he pays for 1000 gms he takes 1200 grams, hence multiplication factor while buying = 1200/1000 = 6/5
Selling: If he charges for 1000 gms he gives only 800 grams, hence multiplication factor while selling = 1000/800 = 5/4
Since selling price = cost price, multiplication factor for price = 1/1 = 1
∴ multiplication factoroverall = multiplication factorprice × multiplication factorquantity while buying × multiplication factorquantity while selling
⇒ multiplication factoroverall = 1 × 6/5 × 5/4 = 6/4 = 3/2
∴ % profit overall = !multiplication factoroverall - 1) × 100% = (3/2 - 1) × 100% = 50%
Hence, option (c).
A shopkeeper cheats while buying as well as while selling. while buying he pays for 20% less than what he takes and while selling he gives 20% less than what he charges for. If his selling price per kg is same as his cost price per kg, what is his profit percentage?
Answer: D
A written solution for this question isn't available yet.
A shopkeeper cheats while buying as well as while selling. while buying he pays for 20% less than what he takes and while selling he charges for 20% more than what he gives. If his selling price per kg is 10% less than his cost price per kg, what is his (approximate) profit percentage?
Answer: B
A shopkeeper cheats while buying as well as while selling. while buying he pays for 20% less than what he takes and while selling he charges for 20% more than what he gives. If his selling price per kg is 10% less than his cost price per kg, what is his (approximate) profit percentage?
Given, his selling price per kg is 10% less than his cost price per kg
∴ Multiplication factor for price = 9/10
While buying if he takes 1000 gms, he pays for only 800 gms.
⇒ multiplication factor while buying = 1000/800 = 5/4
While selling if he gives 1000 gms, he charges for 1200 gms.
⇒ multiplication factor while selling = 1200/1000 = 6/5
∴ Overall multiplication factor for quantity = 5/4 × 6/5 = 3/2
⇒ Overall multiplication = 3/2 × 9/10 = 27/20 = 1.35
∴ % profit = (1.35 - 1) × 100% = 35%
Hence, option (b).
