PE 2 - Percentage | Arithmetic - Percentage
Mr. Manoj saves 30% of his salary every month. But in April, his expenses increase by 20% of his original expenses and he saves $280 less than the amount he saves normally. What is his salary?
- A.
$2000
- B.
$1500
- C.
$2400
- D.
$3000
- E.
$1550
Answer: Option A
Explanation :
Since, savings is 30%, that means Mr. Manoj’s expenses are 70% of his salary.
Let 'x' be the salary and 0.7x be the expenses.
In April, the expenses increase by 20% and become 1.2 × 0.7x = 0.84x
∴ The savings decrease by 0.84x – 0.7x = 0.14x
⇒ 0.14x = 280
⇒ x = $2000
Hence, option (a).
Workspace:
In every box of 120 bulbs, 5% are defective. If a company needs 4,000 non-defective bulbs, what is the minimum number of boxes that it has to purchase?
- A.
32
- B.
34
- C.
35
- D.
36
- E.
None of these
Answer: Option D
Explanation :
5% bulb are defective, i.e., 95% bulb are non-defective.
∴ Each box contains 120 × 95% = 114 non-defective bulbs.
⇒ Minimum number of boxes required = 4000/114 = 35.08
∴ The company has to purchase a minimum of 36 boxes to meet its requirement of bulbs.
Hence, option (d).
Workspace:
Gurmeet purchased a box of chocolates. She ate 20% of them and gave 25% of the remaining chocolates to her friends. Of the remaining chocolates, she ate 20% of it and gave 25% of the remaining chocolates to her friends. Then, she gave 20 chocolates to a guest. Finally, she is left with 35% of the chocolates that she initially had. How many chocolates did Gurmeet eat?
- A.
320
- B.
500
- C.
640
- D.
1250
Answer: Option C
Explanation :
Assuming that the box contains x number of chocolates.
Remaining = 0.36x
After giving chocolates to friends, she gives 20 chocolates to guests also.
∴ Remaining chocolates with her = 0.36x – 20 = 0.35x
⇒ 0.01x = 20
⇒ x = 2000
∴ She had 2000 chocolates at the start.
She ate 0.2x + 0.12x = 0.32x = 640 chocolates
Hence, option (c).
Workspace:
It is given that k = x2 - 2x. If x is doubled, what is the percentage change in k?
- A.
100%
- B.
200%
- C.
121%
- D.
0%
- E.
Cannot be determined
Answer: Option E
Explanation :
If x doubles, it becomes 2x.
∴ New value of k = k’ = 4x2 - 4x.
∴ Percent change in k = (k’ - k)/k × 100, which cannot be determined without knowing the value of x.
Hence, option (e).
Workspace:
The cost of an air ticket is Rs. 2,000 plus tax. If a discount of 50% is allowed on the cost price of the air ticket (not tax), the cost of the ticket decreases by 40%. What is the amount of tax charged on the purchase of a ticket?
- A.
Rs. 400
- B.
Rs. 1000
- C.
Rs. 500
- D.
Rs. 800
- E.
Cannot be determined
Answer: Option C
Explanation :
Original cost = Rs. 2,000 + tax
New cost after discount = 1000 + tax
According to the problem,
60% of (Rs. 2000 + tax) = Rs. 1000 + tax
Rs. 1200 + (0.6) × tax = Rs. 1000 + tax
⇒ 0.4 × tax = 200
⇒ Tax = Rs. 500
Hence, option (c).
Workspace:
Hitesh said to Rohit, if you give me 10% of your pocket money, I will have 100% more than what you will be left with. By how much percent is Hitesh's pocket money more than Rohit's?
- A.
80%
- B.
40%
- C.
50%
- D.
70%
- E.
60%
Answer: Option D
Explanation :
Let the pocket money of Hitesh and Rohit be P and V, respectively.
Now,
⇒ H =
H = R + R
⇒ Hitesh’s money is 7/10 × 100 = 70% more
Hence, option (d).
Workspace:
Two friends x and y have some money with them. ‘x’ gives 40% of his money to ‘y’ and ‘y’ gives 16.67% of the money he now has to ‘x’. Both the friends have the same amounts of money now. If M and N respectively are the amounts of money with ‘x’ and ‘y’ at the beginning, then
- A.
M = N
- B.
M > N
- C.
M < N
- D.
M + N = 600
- E.
None of these
Answer: Option B
Explanation :
Money left with x = 0.6M + (0.167N + 0.0667M) = 0.167N + 0.667M
Money left with y = N + 0.4M – (0.167N + 0.0667M) = 0.833N + 0.333M
Given, both have the same amount of money after these exchanges.
∴ 0.167N + 0.667M = 0.833N + 0.333M
⇒ 0.333M = 0.667N
⇒ M/3 = 2N/3
⇒ M = 2N
⇒ M > N
Hence, option (b).
Workspace:
There are 150 students in a class and 60% of them are girls. 60% of the girls in the class have not studied Math. Taking the class as a whole, 50% of the students have not studied Math. What percentage of boys in the class have studied Math?
- A.
65%
- B.
50%
- C.
40%
- D.
30%
- E.
None of these
Answer: Option A
Explanation :
Given, total number of students = 150
Number of girls who have not studied Math = 60% of 60% of 150 = 54.
Total number of students who have not studied Math = 50% of 150 = 75.
∴ Number of boys who have not studied Math = 75 – 54 = 21.
Total number of boys = 40% of 150 = 60.
∴ percentage of boys who have studied Math = (60 - 21)/60 × 100 = 65%
Hence, option (a).
Workspace:
If a quantity is decreased by 30% and then increased by 50%, by how much percentage does it have to be decreased to bring it back to the original quantity?
- A.
4.76%
- B.
5.85%
- C.
1.33%
- D.
9.5%
- E.
20%
Answer: Option A
Explanation :
Assume the quantity as 100.
It is decreased by 30%, then increased by 50%, and finally decreased by let’s say p%.
Given, final number is same as initial number
∴ = N
⇒ = 1
⇒
⇒ p = 100/21% ≈ 4.76%
Hence, option (a).
Workspace:
x is a positive integer. How many values can 'x' take such that x% of 350 is less than 50?
- A.
13
- B.
14
- C.
15
- D.
12
- E.
16
Answer: Option B
Explanation :
Given, x% of 350 < 50.
⇒ 350x/100 < 50
⇒ x < 100/7 ≈ 14.28
⇒ x can be any integer from 1 till 14.
⇒ x can take 14 values.
Alternately,
Let us calculate 50 is what % of 350.
⇒ 50/350 × 100 = 14.28%
∴ x < 14.28%
⇒ x can be any integer from 1 till 14.
⇒ x can take 14 values.
Hence, option (b).
Workspace:
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