Recurring Decimals | Algebra - Number Theory
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Express in the form of a fraction.
- (a)
- (b)
- (c)
- (d)
Answer: Option D
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Explanation :
Let x = ...(1)
Multiplying both sides with 10
⇒ 10x = ...(2)
(2) - (1)
⇒ 10x - x = - = 7
∴ x =
Alternately,
A number of the form can be written as
Here, a = 0 and b = 7, hence the fractional form of the given number is =
Hence, option (d).
Workspace:
Express in the form of a fraction.
- (a)
- (b)
- (c)
- (d)
None of these
Answer: Option B
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Explanation :
Let x =
Multiplying both sides with 102 (there are 2 non repeating decimal digits i.e., 2 and 1)
⇒ 100x = ...(1)
Now, again multiply with 101 (one repeating digit i.e., 7)
⇒ 1000x = ...(1)
(2) - (1)
⇒ 1000x - 100x = - = 217 - 21 = 196
∴ x =
Alternately,
The shortcut way of writing a recurring decimal in fractional form is
Numerator = (Write the whole number without decimal with recurring set of digits appearing once) - (Write the whole number without decimal and recurring set of digits)
Numerator = 217 - 21 = 196
Denominator = 9..(Number of 9's is same as the number of recurring digits) 0...(Number of 0's is same as the number of non recurring digits after decimal)
Denominator = 900 (There is one recurring digits i.e., 7 and two non recurring digits i.e., 2 and 1)
∴ x =
Hence, option (b).
Workspace:
Express in the form of a fraction.
- (a)
- (b)
- (c)
- (d)
None of these
Answer: Option A
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Explanation :
Let x =
Muliplyting both sides with 101 (There is one non recurring digit after decimal)
⇒ 10x = ...(1)
Muliplyting both sides with 102 (There are two recurring digits after decimal)
⇒ 1000x = ...(2)
(2) - (1)
⇒ 1000x -10x = - = 21376 - 213 = 21163
∴ x =
Alternately,
Numerator of the fraction = 21376 - 213 = 21163
Denominator = 990
∴ x =
Hence, option (a).
Workspace:
Express in the form of a fraction.
- (a)
- (b)
- (c)
- (d)
None of these
Answer: Option C
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Explanation :
Let x =
Numerator of the fraction = 22235 - 222 = 22013
Denominator = 99000
∴ x =
Hence, option (c).
Workspace:
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