Please submit your concern

Explanation:

Now ∆ABC is an isosceles triangle where AB = AC. Let a perpendicular from A meet BC at D. As ∆ABC is isosceles, AD is a perpendicular bisector and BD = CD.

​​​​​​​

Given, Sin b = 3/5

⇒ Cos b = 4/5

In ∆ABD,

Sin b = 35 = ADAB

⇒ AD = 35AB = 3x5

Also, Cos b = 45 = BDAB

BD = 45AB = 4x5

∆ABC, BD = CD = 4x/5

∴ BC = 8x/5

⇒ Area of ∆ABC = ½ × BC × AD = ½ × 8x/5 × 3x/5 = 12x/25 = 0.48x.

Looking at the options we can see that M lies between x2/4 and x2/2. 

Hence, option (a).

Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All