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Explanation:

Let the total units of work = LCM of (10, 12, 15 and 18) = 180

Therefore, efficiencies of Abdul, Bimal, Charlie and Dilbar individually in one day will be 18 units, 15 units, 12 units and 10 units per day respectively. 

Let us check options now:

Option (a): Total work done = 2 × (18 + 15 + 12 + 10) 
= 110 units

Option (b): Total work done = 1 × (15 + 10) + 2 × 12 + 3 × 18 
= 25 + 24 + 54 = 103 units

Option (c): Total work done = 2 × (18 + 2) + 1 × 10 + 3 × 15 
= 40 + 10 + 45 = 95 units

Option (d): Total work done = 2 × (18 + 10) + 1 × 12 + 3 × 15 
= 56 + 12 + 45 = 113 units

Option (e): Total work done = 1 × (18 + 12) + 2 × 15 + 3 × 10 
= 30 + 30 + 30 = 90 units

Hence, option (e).

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