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Explanation:

Consider the diagram below:

Area of a 1 × 1 tile = 1 cm2

Total area of A = 9 × 11 = 99 cm2
∴ Number of 1 × 1 tiles required to cover A = 99/1 = 99 tiles.

Total Area of B + C = 9 × 0.5 + 11 × 0.5 = 20 × 0.5 = 10 cm2
∴ Number of 1 × 1 tiles required to cover B and C = 10/1 = 10 tiles.

Now the remaining area i.e., D = 0.5 × 0.5 = 0.25 cm2

It would be better to but a 0.5 × 0.5 tile to cover D.

∴ The minimum cost of covering entire floor with tiles

= (99 + 10) × 100 + 1 × 30 = 10930

Hence, option (a).

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