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Explanation:

Let P be the principal.

By the given conditions,

P×1+r1003-P=10000

​​​​​​​P×1+r1006-P=25000​​​​​​​​​​​​​​

Let  ​​​​​​​1+r1003=X

Thus,

P(X - 1) = 10000             ...(i)

P(X2 - 1) = 25000           ...(ii)

Dividing (ii) by (i),

X + 1 = 5/2

∴ X = 3/2

Substituting value of X in (i), we get

P = Rs. 20,000

Hence, option (c).

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