If f(x2 – 1) = x4 – 7x2 + k1 and f(x3 – 2) = x6 – 9x3 + k2 then the value of (k2 – k1) is
Explanation:
Substitute x = 0 in f(x2 – 1) = x4 – 7x2 + k1 ⇒ f(–1) = k1 … (i) Substitute x = 1 in f(x3 – 2) = x6 – 9x3 + k2 ⇒ f(–1) = 1 – 9 + k2 … (ii) From (i) and (ii), k1 = –8 + k2 ∴ k2 – k1 = 8 Hence, option (c).
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