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Explanation:

The two lines are 4y – 3x = 2 and 4y – 3x = −7.5

As a1 / a2 = bb2 ≠ c1 / c2; thetwo lines are parallel to each other. 

The distance between the two parallel lines would be the side of the square

i.e. |c1 – c2| / (√a2 + b2)

Here a2 + b2 = (−3)2 + (4)2 = 25 and |c1 – c2| = |2 – (−15/2)| = 19/2

∴ Side of square = (19/2)/5 = 19/10

= 1.9 ∴ Area of square = (1.9)2

= 3.61 sq. units

Hence, option (b).

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