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Explanation:

Observe that the last 16 rows form an A.P. with a = 21, d = 2 and n = 16.
The term before that is 20.

Hence, sum = (19 + 1) + A.P. of 16 terms

Hence, this can even be considered as an A.P. of 17 terms with a = 19 and d = 2

∴ Total parking spaces = 1 + (17/2) × [2(19) + 16(2)] = 1 + 17(19 + 16) = 596

Hence, option (c).

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