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Explanation:

Relative speed of the longer train with respect to the

shorter one = (60 + 48) × 518 = 30 m/s

Let the length of the longer train be x m.

Now the distance travelled by the longer train to cross the shorter train = length of the longer train + length of the shorter train = x + x/2 = 3x/2

The trains cross each other with a speed of (60 + 48) km/h

(60 + 48) km/h = (60 + 48) × 518 = 30 m/s

Therefore,

3x2 = 30 × 15

∴ x = 300 mts

Let the length of the bridge be L.

Now total distance covered in crossing the bridge

= length of the longer train + length of the bridge

= 300 + L

∴ 300 + L = 60 × 518 × 51 = 850

∴ L = 550 mts

Hence, option (a).

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