A bag contains 8 red and 6 blue balls. If 5 balls are drawn at random, what is the probability that 3 of them are red and 2 are blue?
Explanation:
5 balls can be drawn in 14C5 ways.
Out of these 5 balls, 3 will be red in 8C3 × 6C2 ways
∴ Required probability = C38×C26C514 = 60143
Hence, option (d).
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