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Explanation:

We have x2-6x+103-x

= (x-3)2+13-x

= (x-3)23-x + 13-x

= (3 - x) + 13-x

Here, since x < 3, 3 – x > 0

Also, we know that sum of a positive number and its reciprocal is always greater than or equal to 2.

⇒ (3 - x) + 13-x ≥ 2

Hence, option (c).

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