Please submit your concern

Explanation:

By substituting x = 1 or 2 or 3 and so on, we get

x2 = x1 + 1 – 1 = x1 + 0
x3 = x2 + 2 – 1 = x2 + 1 = x1 + 0 + 1
x4 = x3 + 3 – 1 = x3 + 2 = x1 + 0 + 1 + 2
x5 = x4 + 4 – 1 = x4 + 3 = x1 + 0 + 1 + 2 + 3

xn = xn-1 +  0 + 1 + 2 + … + (n – 2)

⇒ x100 = x1 + 0 + 1 + 2 + … + 98 = x1 + (98 × 99)/2

⇒ x100 = -1 + 4851 = 4850

Hence, option (a).

Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All