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Explanation:

Let the thousands, hundreds, tens and units digits be a, b, c and d.

Given, sum of its digits in the thousands, hundreds and tens places is 14
a + b + c = 14   …(1)
The sum of its digits in the hundreds, tens and units places is 15
b + c + d = 15   …(2)

(2) – (1) ⇒ a = d – 1   …(3)

The tens place digit is 4 more than the units place digit ⇒ c = d + 4   …(4)

For the number to be highest possible d should also be highest possible.

Highest possible of d is 5 (from (4)).
∴ highest possible value of c = 9 and that of a = 4

From (1), b = 14 – a – c = 1

∴ The highest such number is 4195

Hence, 4195.

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