Dick is thrice as old as Tom and Harry is twice as old as Dick. If Dick's age is 1 year less than the average age of all three, then Harry's age, in years, is
Explanation:
Let Tom's age to be 'x' years.
∴ Dick's age = 3x.
∴ Harry's age = 6x.
Given, Dick's age is 1 year less than the average age of all three,
∴ 3x = (x + 3x + 6x)/3 – 1
⇒ 9x = 10x – 3
⇒ x = 3
∴ Harry’s age = 6x = 6 × 3 = 18.
Hence, 18.
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