Let m and n be natural numbers such that n is even and 0.2 < m20,nm,n11 < 0..5. Then m – 2n equals
Explanation:
We know, 0.2 < m/20 <0.5 ⇒ 4 < m < 10
Values m can take = {5, 6, 7, 8, 9}
We know, 0.2 < n/11 <0.5 ⇒ 2.2 < n < 5.5
Values n can take = {3, 4, 5}
Since n is even, the only possible value of n is 4.
Also, 0.2 < m20,nm,n11 < 0.5 ⇒ m/5 < n < m/2
Since n = 4 ⇒ 20 > m > 8
The only possible value of m is 9.
∴ m – 2n = 9 – 2 × 4 = 1.
Hence, option (d).
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