In a trapezium ABCD, AB is parallel to DC, BC is perpendicular to DC and ∠BAD = 45°. If DC = 5 cm, BC = 4 cm, the area of the trapezium in sq.cm is
Explanation:
The following diagram can be drawn using the information given.
Since, ∆ADE is an isosceles right triangle hence, DE = AE = 4 cm
⇒ AB = BE + AE = 5 + 4 = 9 cm
∴ Area of trapezium = 12×(CD+AB)×BC = 12×14×4 = 28 cm2.
Hence, 28.
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